SPACEMAS DAY 13 ✨🪐🌎☄️☀️🌕
The large emission nebula on the left of the image is catalogued as IC 1805 and looks somewhat like a human heart. The nebula glows brightly in red light emitted by its most prominent element, hydrogen, but this long-exposure image was also blended with light emitted by silicon (yellow) and oxygen (blue). In the center of the Heart Nebula are young stars from the open star cluster Melotte 15 that are eroding away several picturesque dust pillars with their energetic light and winds. The Heart Nebula is located about 7,500 light years away toward the constellation of Cassiopeia. At the bottom right of the Heart Nebula is the Fishhead Nebula.
Image Credit & Copyright: William Ostling, Telescope Live
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Ic 1805 - The Heart Nebula
Photographer David Joyce - Space From My Backyard: Pictures I Took With A Telescope
M51 - The Whirlpool Galaxy
The Cygnus Loop - A 4
M81 - Bode’s Galaxy
Ngc2244 - The Skull Nebula/Rosette Nebula
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IC 1805, Heart nebula
Constellation of Cassiopeia
Distance: 27.800 ly
Aug 04 2023 -Montcada i Reixac
SONGS TO GET OUT OF OUR SYSTEM (I)
One night of magic rush
The start a simple touch
One night to push and scream
And then relief
Heartbeats,José González
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Best Greetings
Does The Moon Use Pythagorean Rule In Its Motion?
The moon daily displacement =88000 km and during 29.53 days (the moon day period) the displacements total be = 2.598 million km = 2π x 413600 km
The data tells us the moon orbital apogee radius should be 413600 km and also it tells, because the moon daily displacement (88000 km) is so long, the moon should revolve around the Earth through this apogee orbit its radius (413600 km) only and can't revolve around the Earth through any more near orbit…
Not Facts
The moon orbital apogee radius =406000 km only and the moon revolves around the Earth through near orbits and reach to perigee radius (363000 km).
How Can The Moon Do That?
The intelligent moon creates an angle (θ) between its motion direction and its orbit horizontal level by that the real displacement (L) through the orbit be less than (88000 km) because it be (L = 88000 km cos θ), as a result the total displacements be less than (2.598 million km) and that makes the moon orbital apogee radius to be decreased from 413600 km to 406000 km.
We should pay attention to the angle (θ), because this angle controls the moon motion features – where- with the angle (θ) increasing the real displacement (L) be shorter and the moon can revolve around the Earth through more near orbits – but –with the angle (θ) deceasing the real displacement (L) be longer and that pushes the moon far from the Earth to more far orbits.
The moon orbital motion depends on this angle (θ) it tells θ1 = θ0 +1.7
where (θ1) = today angle and (θ0) =yesterday angle
1.7 degrees be used as the moon daily motion degrees for the equation
Notice
As a result for the moon using of the angle (θ), the moon orbital radiuses be defined based on Pythagorean rule – because – the moon uses the angle (θ) in its motion – by that – Each point the moon passes shows this fact – and the radiuses be defined based on one another by Pythagorean rule – let's prove that
(363000 km)2 + (86000 km)2 = (373000 km)2
(373000 km)2 + (86000 km)2 = (384000 km)2
(384000 km)2 + (86000 km)2 = (392000 km)2
(392000 km)2 + (86000 km)2 = (406000 km)2 (error 1%)
Where
363000 km = The Moon Orbital Perigee Radius
373000 km = The Total Solar Eclipse Radius
384000 km = The Moon Orbital Distance
406000 km = The Moon Orbital Perigee Radius
Based on that – we see the moon motion uses Pythagorean rule
Thanks – please read
Physics Nobel Prize For Imaginary Ideas! (Revised)
or
Gerges Francis Tawdrous +201022532292
Peoples' Friendship university of Russia – Moscow
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